两个while循环，if中的 Break 循环 如何回到最外层

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Q: 

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while(True):
    inp = input('Choose the mode: ')
    if inp == '1':
        break
    elif inp == 'SI':
        while(True):
            command = input('Input command: ')
            ser.write(str.encode(command))
            line = ser.readline()
            print(line)
            if command == '1':
                break
        inp = '0'
seems like I can't back to the top while loop again when I input 1 in SI~~~

A: ChatGPT 修改

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while True:
    inp = input('Choose the mode: ')
    if inp == '1':
        break
    elif inp == 'SI':
        while True:
            command = input('Input command: ')
            ser.write(str.encode(command))
            line = ser.readline().decode().rstrip()
            print(line)
            if command == 'out':
                break  # exit the SI mode loop and go back to the top-level loop
        inp = ''  # reset inp to empty string for next iteration


This version adds an extra break statement to exit the SI mode loop and go back to the top-level loop when the command input is 'out'. It also sets inp to an empty string after the break, so that the Choose the mode: prompt appears again for the next iteration.

Note that the decode() and rstrip() methods are used to convert the bytes returned by readline() to a string and remove any trailing white space characters, respectively. This can help with parsing the serial input.

Comment: 有错误在身上的，应该让break 来到 ser.write前面，不然其实所有的命令都会被 ser.write()吞掉：所以应该改成 

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while(True):
    inp = input('Choose the mode: ')
    if inp == '1':
        break
    elif inp == 'SI':
        while(True):
            command = input('Input command: ')
             if command == '1':
                break
            ser.write(str.encode(command))
            line = ser.readline()
            print(line)
           
        inp = '0'

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